append an entry at the end of the integer list If the first entry is zero, write into that one Check, if the current entry already exists Count, how many elements there are in the list
Type | Intent | Optional | Attributes | Name | ||
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type(tem_intList), | pointer | :: | firstEntry |
linked list of resulting elements building the neighbor |
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integer(kind=int_k), | intent(in) | :: | entryPos |
Add that element |
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integer, | intent(inout) | :: | nItems |
how many items are in list |
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logical, | intent(out), | optional | :: | added |
has the current item been added? |
subroutine tem_appendIntListUnique( firstEntry, entryPos, nItems, added ) ! --------------------------------------------------------------------------- !> linked list of resulting elements building the neighbor type(tem_intList),pointer :: firstEntry !> Add that element integer(kind=int_k),intent(in) :: entryPos !> how many items are in list integer,intent(inout) :: nItems !> has the current item been added? logical,intent(out),optional :: added ! --------------------------------------------------------------------------- type(tem_intList),pointer :: currPos ! current position in linked list logical :: found ! has the new entry been found in the existing list? ! --------------------------------------------------------------------------- Added = .false. found = .false. currPos => firstEntry ! The first entry of the list should be given here if(currPos%elem .le. 0) then ! If the element entry of the current entry is zero ! write into that position currPos%elem = entryPos nItems = 1 Added = .true. else ! If element entry /= 0 then find the end of the list do while(associated(currPos%next)) if( currPos%elem .eq. entryPos) found = .true. currPos => currPos%next enddo if( currPos%elem .eq. entryPos) found = .true. if ( .not. found) then ! at the end of the list, append new list item allocate(currPos%next) currPos => currPos%next ! And write to the item currPos%elem = entryPos nItems = nItems + 1 endif endif end subroutine tem_appendIntListUnique